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Delta G^(@) at 500 K for substance 'S' ...

`Delta G^(@)` at 500 K for substance 'S' in liquid state and gaseous state are +100.7 kcal `mol^(-1)` and +103 kcal `mol^(-1)` respectively vapour pressure of liquid 'S' at 500 K is approximately equal to :
`(R=2 cal K^(-1) mol^(01))`

A

0.1atm

B

1atm

C

10atm

D

100atm

Text Solution

Verified by Experts

`X(l) rarr X(g)`
`DeltaG^(@) = DeltaG_(f_(x)(g))^(@) - DeltaG^(@)_(f_(x)(l)), DeltaG^(@) = -RTlnK_(p)`
In this case Kp = pressure of X
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