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The solubility of Sr(OH)(2) at 298 K is ...

The solubility of `Sr(OH)_(2)` at `298 K` is `19.23 g L^(-1)` of solution. Calculate the concentrations cf strontium and hydroxyl ions and the `pH` of the solution.

Text Solution

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Solubility of `Sr(OH)_(2) = 19.23 g//L` at 298 K.
Solubility in `mol//L`,`M=19.23/(121.6g mol^(-))`
`Sr(OH)_(2) to Sr^(2+) + 2OH^(-)`
0.1581 M `2xx0.1581M`
`implies [Sr^(2+)]=0.1581M` and `[OH^(-)]=0.3163M`
In an aqueous solution at `25^@C` :
`[H^(+)][OH^(-)]=K_(w)=10^(-14)implies [H^(+)]=10^(-14)/0.3162 = 3.16xx10^(-14)`
implies`pH=14-0.4997= 13.5003 approx 13.5`
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