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100 mL of 0.15 M HCl is mixed with 100 m...

`100 mL` of `0.15 M HCl` is mixed with `100 mL` of `0.005M HCl` , what is the `pH` of the following solution approxmately

A

2.5

B

1.5

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
Final `(H^(+))=(100xx0.015 + 100xx0.005)/200 =0.01M implies pH=2`
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