The K(SP) for Cr(OH)(3) is 1.6xx10^(-30)...

The `K_(SP)` for `Cr(OH)_(3)` is `1.6xx10^(-30)`. The molar solubility of this compound in water is

A

`root(2)(1.6xx10^(-30))`

B

`root(4)(1.6xx10^(-30))`

C

`root(2)((1.6xx10^(-30))/27)`

D

`(1.6xx10^(-30))/27`

Verified by Experts

The correct Answer is:

C

` Cr(OH)_(3_((s))) to underset(s)(Cr_(aq)^(+3)) + underset(3s)(3OH_(aq)^(-))`
`K_(sp)=27s^(4) implies s=(K_(sp)/27)^(1/4)`

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