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The solubility product of Hg(2)I(2) is e...

The solubility product of `Hg_(2)I_(2)` is equal to

A

`[Hg_(2)^(2+)][I^(-)]`

B

`[Hg^(2+)][I^(-)]`

C

`[Hg_(2)^(2+)][I^(-)]^(2)`

D

`[Hg^(2+)][I^(-)]^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Hg_(2)I_(2_((s))) to Hg_(2aq)^(2+) + 2I_(aq)^(-)`
`K_(sp) = [Hg_(2)^(2+)][I^(-2)]`
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