In a saturated solution of the spatingly soluble strong electrolyte `AgIO_(3)` (molecular mass `=283`) the equilibrium which sets in is
`AgIO_(3) (s)hArrAg^(+)(aq)+IO_(3)^(-)(aq)`
If the solubility product constant `K_(SP)` of `AgIO_(3)` at a given temperature is `1.0xx10^(-8)`, what is the mass of `AgIO_(3)` cotained in `100 mL` of its saturated solution?

Options

A. `28.3xx10^(-2)`g
B. `2.83xx10^(-3)`g
C. `1.0xx10^(-7)` g
D. `1.0xx10^(-4)`g

Answer

B

Explanation

`S^(2)=K_(sp)`
`(x/(0.1xx283))^(2)=1xx10^(-8) implies x=2.83xx10^(-3)g`