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In 1L saturated solution of AgCI [K(sp) ...

In 1L saturated solution of `AgCI [K_(sp) (AgCI) = 1.6 xx 10^(-10)], 0.1 mol` of `CuCI [K_(sp)(CuCI) = 1.0 xx 10^(-6)]` is added. The resultant concentration of `Ag^(+)` in the solution is `1.6 xx 10^(-x)`. The value of "x" is.

A

3

B

5

C

7

D

9

Text Solution

Verified by Experts

The correct Answer is:
C
Since `K_(sp)` of CuCl is very high compared to AgCl.
`[Cl^(-)] =[Cl^(-)]_("from AgCl") + [Cl^(-)]_("from CuCl") approx. [Cl^(-)]_("from CuCl")=10^(-3)`
For AgCl
`1.6xx10^(-10)=[Ag^(+)]xx10^(-3)implies [Ag^(+)]=1.6xx10^(-7)` Hence x = 7
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