Home
Class 12
CHEMISTRY
A solution contain 0.1 MZn^(2+) and 0.01...

A solution contain `0.1 MZn^(2+)` and `0.01 M Cu^(+2)` ins. This solution is saturated by passing `H_(2)S` concentration is `8.1' 10^(-21) M` . Ksp for `ZnS` and `CuS` are `3'10^(-22)` and` 8'10^(-36)` respectively. Which of the following will occur in solution.

A

Only ZnS precipitates

B

Both CuS and ZnS precipitates

C

Only CuS precipitates

D

No precipitation occurs

Text Solution

Verified by Experts

The correct Answer is:
B

For precipitation
`IP gt K_(sp)`
`[Zn^(2+)][S^(2-)] gt K_(sp)`
`[Cu^(2+)][S^(2-)] gt K_(sp)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution containing 0.1 M Zn^(2+) and 0.01 M Cu^(2+) is saturated with H_2S . The S^(2-) concentration is 8.1 xx 10^(-31) M. Will ZnS or CuS precipitate ? K_(sp)(ZnS)=3.0xx10^(-23) and K_(sp)(CuS)=8.0xx10^(-34) .

H_(2)S is passed into one dm^(3) of a solution containing 0.1 mole of Zn^(2+) and 0.1 mole of the Cu^(2+) till the sulphide ion concentration reaches 8.1 xx 10^(-10) moles. Which one of the following statements is true? [K_(sp) of ZnS and CuS are 3 xx 10^(-22) and 8 xx 10^(-36) respectively]

The OH^- concentration of a solution is 1.0 xx 10^(-10) M. The solution is

A solution contains 0.1M H_(2)S and 0.3M HCI . Calculate the conc.of S^(2-) and HS^(-) ions in solution. Given K_(a_(1)) and K_(a_(2)) for H_(2)S are 10^(-7) and 1.3xx10^(-7) respectively.

A solution containing both Zn^(2+) and Mn^(2+) ions at a concentration of 0.01M is saturated with H_(2)S . What is pH at which MnS will form a ppt ? Under these conditions what will be the concentration of Zn^(2+) ions remaining in the solution ? Given K_(sp) of ZnS is 10^(-22) and K_(sp) of MnS is 5.6 xx 10^(-16), K_(1) xx K_(2) of H_(2)S = 1.10 xx 10^(-21) .