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The solubility of Pb(OH)(2) in water is ...

The solubility of `Pb(OH)_(2)` in water is `6.7xx10^(-6)`M. Calculate the solubility of `Pb(OH)_(2)` in a buffer solution of `pH=8`.

A

`1.2xx10^(-2)`

B

`1.6xx10^(-3)`

C

`1.6xx10^(-2)`

D

`1.2xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`[Pb^(2+)][OH^(-2)]=4s^(2)`
`[Pb^(2+)]=(4xx(6.7xx10^(-6))^(2))/10^(-6)^(2) = 1.2xx10^(-3)`
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