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A weak acid of dissociation constant 10^...

A weak acid of dissociation constant `10^(-5)` is being titrated with aqueous NaOH solution . The pH at the point of one third of neutralization of the acid will be

A

5 + log2 – log3

B

5 – log2

C

5-log3

D

5-log6

Text Solution

Verified by Experts

The correct Answer is:
B
After (1/4)th neutralization
`(["sal t"])/(["Acid"])= (1//3)/(2//3)=1/2`
`pH=pK_(a)+"log" (["sal t"])/(["Acid"])=5-log2`
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