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K(sp)(AgCl) gt K(sp)(AgBr) gt K(sp)(AgI)...

`K_(sp)(AgCl) gt K_(sp)(AgBr) gt K_(sp)(AgI)`. This means that :

A

AgCl is less ionised than AgBr and AgI

B

Both AgBr and AgI are less soluble than AgCl

C

AgI is most soluble

D

AgBr is more soluble than AgCl but less soluble than AgI

Text Solution

Verified by Experts

The correct Answer is:
B
Lower the `K_(sp)`, lower is the solubility (All the salts are of the type AB)
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