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Which statement is false ? (Assume compl...

Which statement is false ? (Assume complete dissociation in each case)

A

If 2.0 L of a solution of `H_(2)SO_(4)` contains 0.1 mole, then pH of the solution is 1

B

The concentration of `OH^(-)` ions in 0.005 M HNO3 is `2.0xx10^(-12) (mol)/L`

C

The pH of 0.01 M KOH is 12

D

In a 0.001 M solution of NaOH the concentration of `H^(+)` ions is `10^(-3) (mol)/L`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is false regarding the dissociation of acids and bases, we will analyze each statement step by step. ### Step 1: Analyze the first statement regarding H2SO4 - **Given**: 2 liters of H2SO4 solution contains 0.1 moles. - **Dissociation**: H2SO4 dissociates completely into 2 H⁺ ions and 1 SO₄²⁻ ion. - **Calculation**: - Moles of H⁺ produced = 2 × 0.1 = 0.2 moles. - Concentration of H⁺ = Moles of H⁺ / Volume = 0.2 moles / 2 L = 0.1 M. - **pH Calculation**: - pH = -log[H⁺] = -log(0.1) = 1. - **Conclusion**: The statement regarding the pH being 1 is correct. ### Step 2: Analyze the second statement regarding HNO3 - **Given**: 0.005 molar HNO3. - **Dissociation**: HNO3 dissociates into H⁺ and NO₃⁻. - **Calculation**: - Concentration of H⁺ = 0.005 M. - Using the ion product of water (Kw = 1 × 10⁻¹⁴): - [OH⁻] = Kw / [H⁺] = 1 × 10⁻¹⁴ / 0.005 = 2 × 10⁻¹² M. - **Conclusion**: The statement regarding the concentration of OH⁻ ions is correct. ### Step 3: Analyze the third statement regarding KOH - **Given**: 0.01 molar KOH. - **Dissociation**: KOH dissociates into K⁺ and OH⁻. - **Calculation**: - Concentration of OH⁻ = 0.01 M. - pOH = -log(0.01) = 2. - pH = 14 - pOH = 14 - 2 = 12. - **Conclusion**: The statement regarding the pH being 12 is correct. ### Step 4: Analyze the fourth statement regarding NaOH - **Given**: 0.001 molar NaOH. - **Dissociation**: NaOH dissociates into Na⁺ and OH⁻. - **Calculation**: - Concentration of OH⁻ = 0.001 M. - Using the ion product of water (Kw = 1 × 10⁻¹⁴): - [H⁺] = Kw / [OH⁻] = 1 × 10⁻¹⁴ / 0.001 = 1 × 10⁻¹¹ M. - **Conclusion**: The statement that the concentration of H⁺ ions is 10⁻³ M is incorrect. The correct concentration is 10⁻¹¹ M. ### Final Conclusion The false statement is the one regarding the concentration of H⁺ ions in a 0.001 molar solution of NaOH, which is stated to be 10⁻³ moles per liter, but it is actually 10⁻¹¹ moles per liter. ---

To determine which statement is false regarding the dissociation of acids and bases, we will analyze each statement step by step. ### Step 1: Analyze the first statement regarding H2SO4 - **Given**: 2 liters of H2SO4 solution contains 0.1 moles. - **Dissociation**: H2SO4 dissociates completely into 2 H⁺ ions and 1 SO₄²⁻ ion. - **Calculation**: - Moles of H⁺ produced = 2 × 0.1 = 0.2 moles. - Concentration of H⁺ = Moles of H⁺ / Volume = 0.2 moles / 2 L = 0.1 M. ...
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