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The ionisation constant of benzoic acid ...

The ionisation constant of benzoic acid `(PhCOOH)` is `6.46 xx 10^(-5)` and `K_(sp)` for silver benzoate is `2.5 xx 10^(-3)`. How many times is silver benzoate more soluble in a buffer of `pH 3.19` compared to its solubility is pure water?

Text Solution

Verified by Experts

The correct Answer is:
3.317
In pure water `C_(6)H_(5)COOAg to underset(s-x)(C_(6)H_(5)COO^(-)) + underset(s)(Ag^(+))`
`s(s-x)=2.5xx10^(-13)`
`x^(2)/(s-x) = 10^(-14)/((6.46xx10^(-5))) to` Get’s
In buffer `C_(6)H_(5COO^(-) + H^(+) to C_(6)H_(5)COOH`
`s^(‘)(s^(‘)-x)=2.5xx10^(-13)`
`( s^(‘)(s^(‘)-x)xx10^(-3.19))/x^(‘)=6.46xx10^(-5) to `Get’s
`s^(‘)/s=3.317`
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