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The solubility of Pb(OH)(2) in water is ...

The solubility of `Pb(OH)_(2)` in water is `6.7xx10^(-6)`M. Calculate the solubility of `Pb(OH)_(2)` in a buffer solution of `pH=8`.

Text Solution

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The correct Answer is:
`1.2xx10^(3)molL^(-1)`
`Pb(OH)_(2) to Pb^(2+)(aq) + 2OH^(-)(aq)`
`K_(sp)=4s^(3)=4(6.7xx10^(-6))^(3)`
`K_(sp)=1.2xx10^(-15)`
`Pb(OH)_(2) to Pb^(2+)(aq)` [in buffer solution of pH=8]
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