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The first and second dissociation consta...

The first and second dissociation constant of an acid `H_(2)A` are `1.0xx10^(-5)` and `5.0xx10^(-10)` repectively. The overall dissociation constant of the acid will be

A

`5.0xx10^(-5)`

B

`5.0xx10^(15)`

C

`5.0xx10^(-15)`

D

`0.2xx10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(2)A to HA^(-) + H^(+)`
`therefore K_(1) = 1.0xx10^(-5)=([H^(+)][HA^(-)])/([H_(2)A]) `(given)
`HA^(-) to H^(+) + A^(2-)`
` therefore K_(2) = 5.0xx10^(-10)=([H^(+)][=A^(2-)])/([HA^(-)]) `(given)
`(K =[H^(2+)])[(A^(2-)])/([H_(2)A]) = K_(1)xxK_(2)= (1.0xx10^(-5))xx(5xx10^(-10))=5xx10^(-15)`
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