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A mixture of 100m mol of Ca(OH)(2) and ...

A mixture of 100m mol of `Ca(OH)_(2)` and 2g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of `OH^(-)` in resulting solution, respectively, are: (Molar mass of `Ca(OH)_(2),Na_(2)SO_(4)` and `CaSO_(4)` are 74, 143 and 136 g `mol^(-1)` respectively, `K_(sp)` of `Ca(OH)_(2)` is `5.5xx10^(-6)` )

A

`13.6 g, 0.28 mol L^(-1)`

B

`1.9 g, 0.14 mol L^(-1)`

C

`1.9 g, 0.28 mol L^(-1)`

D

`13.6 g, 0.14 mol L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ca(OH)_(2) + Na_(2)SO_(4) to CaSO_(4) + 2NaOH`
100 mmol 14 mmol
- - 14 mmol 28 mmol
Mass of `CaSO_(4) = 14xx10^(-3)xx136=1.9g`
`[OH^(-)]=28/100 = 0.28M`
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