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The molar solubility of Cd(OH)(2) is 1.8...

The molar solubility of `Cd(OH)_(2)` is `1.84xx10^(-5)M` in water. The expected solubility of `Cd(OH)_(2)` in a buffer solution of pH = 12 is

A

`2.49/1.84 xx10^(-9)M`

B

`2.49xx10^-(10)`

C

`6.23xx10^(-11)`

D

`1.84xx10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Cd(OH)_(2) to Cd^(2+) + 2OH^(-)`
`K_(sp)=[Cd^(2+)][OH^(-2)]`
Solubility `s=[Cd^(2+)]=K_(sp)/([OH^(-2)])`
pH of the buffer =12
pOH = 2, `[OH]=10^(-2)`
`K_(sp)=4s^(2)=4(1.84xx10^(-5))^(3)`
`[Cd^(+2)]=(4[1.84xx10^(-5)]^(3))/(10^(-4)) = (4xx6.23xx10^(-15))/10^(-4) =2.49xx10^(-10)M`
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