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3 gram of acetic acid is mixed in 250 mL...

3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL of this solution is now taken is another container `1/2` mL of 5M NaOH is added to this. Find the pH of this solution. (`pK_a = 4.74`)

Text Solution

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The correct Answer is:
5.23
mmoles of `CH_(3)COOH=50`
mmoles of HCl=25
mmoles of `CH_(3)COOH` in `20ml= 50/500 xx20=2`
mmoles of HCl in 20mL`=25/500 xx20=1`
Now `NaOH + HCl to NaCl + H_(2)O`
t=0 2.5 1
`t_(end)` 1.5 0
` CH_(3)COOH + NaOH to CH_(3)COONa + H_(2)O`
t=0 2 1.5 0
`t_(end)` 0.5 0 1.5
In the end we have an acidic buffer
`pH = pK_(a) + "log"(["salt’])/(["Acid’])`
`pH=5.23`
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