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At 90^(@)C pure water has [H(3)O^(+)] as...

At `90^(@)C` pure water has `[H_(3)O^(+)]` as `10^(-6) mol L^(-1)`. What is the value of `K_(w)` at `90^(@)C`?

A

`10^(-6)`

B

`10^(-12)`

C

`10^(-14)`

D

`10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(w) = [H_(3)O^(+)][OH^(-)] = 10^(-6)xx10^(-6) = 10^(-12)`
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