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The solubility of Mg (OH)(2) in pure wat...

The solubility of `Mg (OH)_(2)` in pure water is `9.57 xx 10^(-3) gL^(-1)`. Calculate its solubility (in `gL^(-1))` in `0.02M Mg(NO_(3))_(2)` solution.

Text Solution

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In pure water, solubility = `9.57/58 xx 10^(-3)M = 1.65 xx 10^(-4)M`
`K_(sp) = 4S^(3) = 4 (1.65 xx 10^(-4))^(3) = 1.8 xx 10^(-11)`
In 0.02 M `Mg(NO_(3))_(2),`
Solubility of `Mg(OH_(2)) = sqrt(K_(sp)/[Mg^(2+)]) xx 1/2 = 1.5 xx 10^(-5) molL^(-1)`
` = 1.5 xx 10^(-5) xx 58 gL^(-1) = 8.7 xx 10^(-4) gL^(-1)`
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