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How many mole of HCI will be required t...

How many mole of HCI will be required to prepare one litre of buffer solution (containing `NaCN+ HCI`) of `pH 8.5` using `0.01`g formula weight of NaCN ? `K_(HCN)=4.1xx10^(-10))`

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HCN for buffer will be formed by the reaction
`NaCN + HCl rarr NaCl + KCN`
mmol of NaCN present initially =` 0.01/49 xx 1000 = 0.2`
let x mmol of HCl is added to that x m mol of NaCN will be neutralized forming x mmol of HCN.
`pH = pK_(a) + log[NaCN]/[HCN]`
`8.5 = -log(4.1 xx 10^(-10))+ log 0.2-x/x implies x = 0.177 mmol`
`HClO_(4)` is strongest acid.
As its conjugate base is most stable
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