For the reaction
`Ag(CN)_(2)^(ɵ)hArr Ag^(o+)+2CN^(ɵ)`, the `K_(c )` at `25^(@)C` is `4 xx10^(-19)` Calculate `[Ag^(o+)]` in solution which was originally `0.1 M` in `KCN` and `0.03 M` in `AgNO_(3)`.

Explanation

`Ag^(+) + 2CN^(-) to Ag(CN)_(2)^(-)`
initial 0.03 0.10 0
Equilibrium x 0.10-0.06 0.03
`K=1/(4xx10^(-19)) = 2.5xx10^(-18)impliesK=2.5xx10^(18)=0.03/((0.04)^(2)x)`
`x=7.50xx10^(-18)M`