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If molarity = molality and density of th...

If molarity = molality and density of the solution is 2gm/ml then `W_("solute"):W_("solvent")` would be

A

`1:2`

B

`2:1`

C

`1:1`

D

`1:3`

Text Solution

Verified by Experts

`:.` Given that
Molarity =molality
`("moles")/(V(sdn)(L))=("moles")/(W("solvent")(kg))`
`implies W_(("solvent"))` is numerically equal to volume of the solution.
`V_(("so In"))=(W("solution"))/(d("solution"))implies(w("solution"))/(d("solution"))=W` (solvent)
`((W_("solution"))/(W_("solvent"))-d_("solution"))`
As `d=2` gm/ml
`impliesW_("solution")=2W_("solvent")impliesW_("solute")=W_("solvent")`
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