The vapour pressure of water at `25^(@)C` is 18 mmHg. If 18 g of glucose`(C_(6)H_(12)O_(6))` is added to 178.2 g of water at `20^(@)C`, the vapour pressure of the resulting solution will be :

Options

A. 17.70 mmHg
B. 15.750 mmHg
C. 16.500 mmHg
D. 17.82 mmHg

Explanation

To solve the problem of finding the vapor pressure of the resulting solution after adding glucose to water, we can follow these steps:

### Step 1: Identify the given data
- Vapor pressure of pure water at 25°C, \( P_0 = 18 \, \text{mmHg} \)
- Mass of glucose, \( W_2 = 18 \, \text{g} \)
- Mass of water, \( W_1 = 178.2 \, \text{g} \)

### Step 2: Calculate the number of moles of glucose (solute)
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