Home
Class 12
CHEMISTRY
When 25 g of a non-volatile solute is di...

When 25 g of a non-volatile solute is dissolved in 100 g of water, the vapour pressure is lowered by `2.25xx10^(-1)mm` of Hg. What is the molecular weight of the solute? [`P^(@)= 17.73` mm]

A

2.06

B

3.02

C

3.55

D

2.76

Text Solution

AI Generated Solution

To find the molecular weight of the non-volatile solute, we can use the concept of relative lowering of vapor pressure. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the given data - Mass of solute (non-volatile) = 25 g - Mass of solvent (water) = 100 g - Vapor pressure lowering (ΔP) = 2.25 x 10^(-1) mm Hg = 0.225 mm Hg - Vapor pressure of pure solvent (P₀) = 17.73 mm Hg ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of water at 20^(@)C is 17.54mm . When 20g of non - ionic substance is dissolved in 100g of water, the vapour pressure is lowered by 0.30mm . What is the molecular mass of the substance ?

When 25g of a non-volatile solute is dissolved in 100g of water, the vapour pressure is lowered by 0.225 mm. If the vapour pressure of water at 25^(@)C is 17.5 mm, what is the molecular mass of solute ?

Vapour pressure of benzene at 30^(@)C is 121.8 mm. When 15 g of a non-volatile solute is dissolved in 250 g of benzene its vapour pressure decreased to 120.2 mm. The molecular weight of the solute is (mol. Weight of solvent = 78)