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Two liquids X and Y form an ideal soluti...

Two liquids X and Y form an ideal solution. At 300K, vapour pressure of the solution containing 1 mol of X and 3 mol of Y is 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mmHg) of X and Y in their pure states will be, respectively

A

200 and 300

B

300 and 400

C

400 and 600

D

500 and 600

Text Solution

Verified by Experts

`P_(T)=P_(X)^(@)X_(x)+P_(Y)^(@)X_(Y)`
`X_(x)=` mol fraction of X
`X_(Y)=` mol fraction of Y
`550=P_(X)^(@)(1/(1+3))+P_(Y)^(@)(3/(1+3))`
`550(4)=P_(X)^(@)+3P_(4)^(@)`………1
`:.560=P_(X)^(@)(1/(1+4))+P_(Y)^(@)(4/(1+4))`
`:.560(S)=P_(x)^(@)+4P_(Y)^(@)`.........2
By solving 1 and 2
We get `P_(x)^(@)=400m Hg" ", " "P_(Y)^(@)=600 mm Hg`
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