Home
Class 12
CHEMISTRY
The degree of dissociation (alpha) of a...

The degree of dissociation `(alpha)` of a weak electrolyte `A_(x)B_(y)` is related to van't Hoff factor (i) by the expression

A

`alpha=(i-1)/(x+y-1)`

B

`alpha=(i-1)/((x+y+1))`

C

`alpha=((x+y-1))/(i-1)`

D

`alpha=((x+y+1))/(i-1)`

Text Solution

Verified by Experts

`underset(1-alpha)(A_(x)B_(y))tounderset(x alpha)(xA^(y^(+)))+underset(y alpha)(yB^(x^(-)))`
`i=1-alpha+x alpha+y alpha=1 + alpha(x+y-1)`
`:.alpha=(i-1)/((x+y-1))`
Promotional Banner

Similar Questions

Explore conceptually related problems

The degree of dissociation (alpha) of a weak electrolyte, A_(x)B_(y) is related to van't Hoff's factor (i) by the expression:

The degree of dissociation (alpha) of a weak electrolyte, A_(2)SO_(4) is related to Vant Hoff factor (i) by the expression

van't Hoff factor (i) is given by the expression

What is Van't Hoff factor ?

If van't Hoff factor i=1,then

, van't -Hoff factor (i) for this reaction is:

The van’t Hoff factor can be expressed as :

Van't Hoff factor is _____.