At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea `=60 g "mol"^(-1)`)

Options

A. 0.027 mm Hg
B. 0.031 mm Hg
C. 0.017 mm Hg
D. 0.28 mm Hg

Explanation

To solve the problem of lowering of vapor pressure when urea is dissolved in water, we can follow these steps:

### Step 1: Calculate the number of moles of urea
Given:
- Mass of urea = 0.60 g
- Molar mass of urea = 60 g/mol

Using the formula for moles:
...