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For a dilute solution containing 2.5 g o...

For a dilute solution containing `2.5 g` of a non-volatile non-electrolyte solution in `100g` of water, the elevation in boiling point at `1` atm pressure is `2^(@)C`. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of `Hg)` of the solution is:
(take `k_(b) = 0.76 K kg mol^(-1))`

A

724

B

740

C

736

D

718

Text Solution

Verified by Experts

`DeltaT_(B)=K_(b)xxm`
`2=0.76xxm " "implies" "m=2/0.76`
`m=(w_(2)xx1000)/(M_(2)xxW_(1)("in grams"))=2.5/(M_(2)xx100)xx1000`
`2/0.76=(2.5xx10)/(M_(2))impliesM_(2)=(2.5xx10)/2xx0.76`
`(p_("solvent")^(@)-p_("solutte"))/(p_("solvent")^(@))=x_("solute")`
`p_("solvent")^(@)=1atm=760` mm Hg
`(760-p_("solvent")^(@))/760=(2.5//M_(2))/(100//18)`
`760-p_("solute")=(2.5xx2)/(2.5xx10xx0.76)xx18/100xx760`
`760-p_("solute")=36impliesp_("solute")=724` mm hg
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