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20/(d)/(dx)[tan^(-1)((a-x)/(1+ax))]=squa...

20/(d)/(dx)[tan^(-1)((a-x)/(1+ax))]=square(114)

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(d)/(dx) [tan^(-1) ((a-x)/(1+ ax))] is

(d)/(dx)[tan^(-1)((ax-b)/(bx+a))]=

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