`2^(2/3)*2^(1/7)=`

Simplify : (i) 2^(2/3)xx2^(1/5) (ii) (1/3^(3))^(7) (iii) 11^(1/2)/11^(1/4) (iv) 7^(1/2)*8^(1/2)

Simplify : (i) 2^(2/3). 2^(1/5) (ii) (1/(3^3))^7 (iii) (11^(1/2))/(11^(1/4)) (iv) 7^(1/2). 8^(1/2)

Solve : (i) 2^((2)/(3))*2^((1)/(4)) (ii) ((1)/(3^(3)))^(7) (iii) (11^((1)/(2)))/(11^((1)/(4))) (iv) 7^((1)/(2))*8^((1)/(2))

Simplify : (i) 2^(2/3). 2^(1/5) (ii) (1/(3^3))^7 (iii) (11^(1/2))/(11^(1/4)) (iv) 7^(1/2). 8^(1/2)

Simplify : (i) 2^(2//3).2^(1//5) (ii) ((1)/(3^(3)))^(7) (iii) (11^((1)/(2)))/(11^((1)/(4))) (iv) 7^(1//2).8^(1//2)

(2/7)^3xx(1/2)^3

Find sum of first 15 term of series 1+6+(9(1^(2)+2^(2)+3^(2)))/(7)+(12(1^(2)+2^(2)+3^(2)+4^(2)))/(9) (1) 7620 (2) 7280 (3) 7820 (4) 7067

The sum of series 1+6+(9(1^(2)+2^(2)+3^(2)))/(7) + (12(1^(2)+2^(2)+3^(2)+4^(2)))/(9)+(15(1^(2)+2^(2)+...+5^(2)))/(11)+... up to 15 terms is

The sum of series 1+6+(9(1^(2)+2^(2)+3^(2)))/(7) + (12(1^(2)+2^(2)+3^(2)+4^(2)))/(9)+(15(1^(2)+2^(2)+...+5^(2)))/(11)+... up to 15 terms is

The sum of series 1+6+(9(1^(2)+2^(2)+3^(2)))/(7) + (12(1^(2)+2^(2)+3^(2)+4^(2)))/(9)+(15(1^(2)+2^(2)+...+5^(2)))/(11)+... up to 15 terms is