[1,bc,a(b+c)],[4,1,ca,b(c+a)],[1,ab,c(a+b)]

Prove the following : [[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]] =0

|[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]|=0

Without expanding,show that the following determinant vanishes. abs ((1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b)))

|(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))|=

|{:(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b)):}|=0

|(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))|= 0

What is the value of the determinant |(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))| ?

Using the properties of determinants,prove det[[1,bc,bc(b+c)1,ca,ca(c+a)1,ab,ab(a+b)]]

det[[1,bc,bc(b+c)1,ca,ca(c+a)1,ab,ab(a+b)]]=0