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Metabolism of one plamitic acid yields A...

Metabolism of one plamitic acid yields ATP

A

36 ATP

B

56 ATP

C

129 ATP

D

48 ATP

Text Solution

Verified by Experts

The correct Answer is:
C
One plamitic acid, `C_(16)H_(32)O_(2)`, yields eight acetyl CoA molecules seven `(NADH+H^(+),FADH_(2))` through `beta`-oxidation. One acetyl CoA yields 12 ATP in Krebs cycle. One `NADH+" one "FADH_(2)` are equivalent to 5 ATP. The total is `(8xx12)+(7xx5)=131` ATP. Two molecules of ATP are used in initiation of `beta`-oxidation.
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