In an experiment on pea plant, pure plants with yellow round seeds (YYRR) were crossed with plants producing green wrinkled seeds (yyrr). What will be phenotypic ratio of `F_(1)` progeny ?

Options

A. 9 yellow round : 3 round green : 3 wrinkled yellow : 1 green wrinkled
B. All yellow round
C. 1 round yellow : 1 round green : 1 wrinkled yellow : 1 wrinkled green
D. All wrinkled green

Answer

To determine the phenotypic ratio of the F1 progeny from the cross between pure plants with yellow round seeds (YYRR) and plants producing green wrinkled seeds (yyrr), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes of Parent Plants:**
- The first parent plant has the genotype YYRR (homozygous dominant for both traits).
- The second parent plant has the genotype yyrr (homozygous recessive for both traits).

2. **Determine the Gametes Produced by Each Parent:**
- The gametes from the first parent (YYRR) can only be YR (since both alleles are dominant).
- The gametes from the second parent (yyrr) can only be yr (since both alleles are recessive).

3. **Perform the Cross:**
- When we cross the gametes from both parents, we get:
- YR (from YYRR) x yr (from yyrr) → All offspring will have the genotype YyRr.

4. **Determine the Genotype of the F1 Progeny:**
- The genotype of the F1 progeny is YyRr, which is heterozygous for both traits.

5. **Determine the Phenotype of the F1 Progeny:**
- Since yellow (Y) is dominant over green (y) and round (R) is dominant over wrinkled (r), the phenotype of the F1 progeny will be:
- Yellow seeds (due to Y) and round seeds (due to R).

6. **Conclusion on Phenotypic Ratio:**
- All F1 progeny will exhibit the same phenotype: yellow and round seeds.
- Therefore, the phenotypic ratio of the F1 progeny is 100% yellow round seeds or 1:0.

### Final Answer:
The phenotypic ratio of the F1 progeny is 1:0 (all yellow round seeds).

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