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A group of 2n boys and 2n girls is rando...

A group of 2n boys and 2n girls is randomly divided into two equal groups. The probability that each group contains the same number of boys and girls is (A) 1/2 (B) 1/n (c) 1/2n (D) None of these

Text Solution

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`2n+2n=4n`
According to question
`.^(4n)C_(2n)`
`P=((.^(2n)C_n)*(.^(2n)C_(2n)))/(.^(4n)C_(2n)`.
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