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Prove that : tan^(-1)((63)/(16))=sin^(-1...

Prove that : `tan^(-1)((63)/(16))=sin^(-1)((5)/(13))+cos^(-1)((3)/(5))`

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R.H.S=`sin^(-1)5/(13)+cos^(-1)3/5`
`sin^(-1)5/(13)=a`
=`sina=5/13 or cosa=12/13`
or` tana=5/12`
now`cos^(-1)3/5=b`
`cosb=3/5 or sinb=4/5`
or `tanb=3/4`
so,R.H.S=`tan^(-1)(5/12)+tan^(-1)(3/4)`
...
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