A gas is found to obey the law `P^(2)` V= constant the innitial temperature and volume are `T_(0)` and `V_(0)`. If the gas expands to volume `2V_(0)` , its final temperature becomes-

Options

A. `sqrt(2) T_(0)`
B. `2T_(0)`
C. `T_(0)//2`
D. ` T_(0)//sqrt(2)`

Answer

A

Explanation

`P^(2)V` = constant `implies (T^(2))/(V)` = constant
`implies T_(2) = sqrt((v_(2))/(v_(1))) T_(1) = sqrt2 T_(0)`