For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current I drawn the cell. The emf and the internal resistance of the cell are E and r, respectively. Then

Options

A. 2V , `0.5 Omega`
B. 2V , `0.4 Omega`
C. `gt` 2V , `0.5 Omega`
D. `gt` 2 V , `0.4 Omega`

Answer

B

Explanation

`varepsilon = 2V`
`(varepsilon)/(r) = 5`
`(2)/(r) = 5`
`r = (2)/(5) = 0.4 Omega`