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A double-slit experiment is immersed in ...

A double-slit experiment is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and screen is 1.33 m. The slits are illuminated by a parallel bam of light whose wavelength in air is `6830 Å`. Then the fringe width is

A

`6.3 xx 10^(-4) `m

B

`8. 3 xx 10^(-4)`m

C

`6.3 xx 10^(-2) `m

D

`6.3 xx 10^(-5) `m

Text Solution

Verified by Experts

The correct Answer is:
A

`B_(m) = (B_("air"))/(mu) = (D lambda)/(d xx mu) = 6.3 xx 10^(-4)` m
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