A six coordination complex of formula `CrCl_(3)*6H_(2)O` has green colour. A 0.1 M solution of the complex when treated with excess of `AgNO_(3)` gave 28.7g of white precipitate. The formula of the complex would be:

Options

A. ` [Cr(H_(2)O)_(6)]Cl_(3)`
B. `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2) O`
C. `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
D. `[Cr(H_(2)O)_(3)Cl_(3)]`

Answer

B

Explanation

`Crunderset(0.1 "mol")(Cl_(3))*6H_(2)O + AgNO_(3) ("excess") to underset(28.7 g) (AgCl)`
No. of moles of AgCl = `(28.7)/(143.5)` = 0.2 mol