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NH(4)HS(s)hArrNH(3)(g)+H(2)S(g) The3 eq...

`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)`
`The3 equilibrium pressure at `25^(@)C` is 0.660 atm . What is `K_(p)` for the reaction ?

A

`0.109`

B

`0.218`

C

`1.89`

D

`2.18`

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(4)HS(s) hArr underset(P)(NH_(3)(g)) + underset(P)(H_(2)S(g))`
Equ. Pressure -
2P = `0.660`
P = `0.330`
`K_(p) = P_(NH_(3)) . P_(H_(2)S)`
= `0.33 xx 0.33 = 0.109`
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