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2.4 g of pure Mg (at. Mass = 24) is drop...

2.4 g of pure Mg (at. Mass = 24) is dropped in 100 mL of 1 M HCl . Which of the following statement is wrong ?

A

`1.12` L of hydrogen is produce as S.T.P.

B

`0.05` mol of magnesium is left behind

C

HCl is the limiting reagent .

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

`{:("Mg" " " + " " 2HCl " " to MgCl_(2) + H_(2)), (2.4 g """""" " (1M, 100"ml")" ), (0.1 "mol" " " 0.1 "mol"), (underline(-0.05)), (0.05 "mol"):}`
HCl is a limiting reagent
`0.1` mol HCl give `(0.1)/(2)` mol `H_(2)` or `1.12` lit `H_(2)` at STP
`0.05` mol Mg left
`therefore` None of these is wrong.
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