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In the quadratic equation `ax^2 + bx + c = 0`, if `Delta = b^2-4ac and alpha + beta, alpha^2 + beta^2, alpha^3 + beta^3` are in GP. where `alpha, beta` are the roots of `ax^2 + bx + c =0`, then

A

`Delta ne 0`

B

`b Delta = 0 `

C

`cb ne 0`

D

`c Delta = 0 `

Text Solution

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The correct Answer is:
D

`(-b)/(a) , (b^(2) - 2ac)/(a^(2)) , (-b^(3) + 3abc)/(a^(3))` are in G.P.
`(b^(2) - 2ac)^(2) = (-b^(3) + 3abc)(-b)`
`b^(4) + 4a^(2) c^(2) - 4ab^(2) c = b^(4) - 3ab^(2)c`
`ab^(2)c - 4a^(2)c^(2) = 0`
a.c.`(b^(2) - 4ac) = 0 `
`implies c. Delta = 0 `
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