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A line L is perpendicular to the curve y...

A line `L` is perpendicular to the curve `y= (x^2) / 4 - 2` at its point `p` and passes through `(0, -1)`. The coordinates of the point p are

A

`( 2 , -1)`

B

(6 , 7)

C

`(0 , -2)`

D

(4 , 2)

Text Solution

Verified by Experts

The correct Answer is:
D
Let the point is `(h , (h^(2) - 8)/(4))` , equation of normal
`( y (h^(2) - 8)/( 4)) = (-2)/(h) (x - h)`,
`because (10 , -1)` lies on it `h^(3) + 4h - 80 = 0`
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