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The mean age of a combined group of men ...

The mean age of a combined group of men and women is 25 yrs . If mean age of men is 26 and that of women is 21 , then percentage of men and women in the group , is ,

A

60 , 40

B

80 , 20

C

20 , 80

D

30 , 70

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To solve the problem, we will use the concept of weighted averages. Let's denote the number of men as \( m \) and the number of women as \( w \). ### Step-by-Step Solution: 1. **Understand the Given Information**: - Mean age of the combined group (men and women) = 25 years - Mean age of men = 26 years - Mean age of women = 21 years 2. **Set Up the Equation for the Mean**: The mean age of the combined group can be expressed as: \[ \text{Mean} = \frac{(m \times 26) + (w \times 21)}{m + w} = 25 \] 3. **Multiply Both Sides by \( m + w \)**: This eliminates the denominator: \[ (m \times 26) + (w \times 21) = 25(m + w) \] 4. **Expand the Right Side**: \[ 26m + 21w = 25m + 25w \] 5. **Rearrange the Equation**: Move all terms involving \( m \) and \( w \) to one side: \[ 26m - 25m = 25w - 21w \] Simplifying gives: \[ m = 4w \] 6. **Express the Total Number of People**: The total number of people in the group is: \[ m + w = 4w + w = 5w \] 7. **Calculate the Percentages**: - Percentage of men: \[ \text{Percentage of men} = \left(\frac{m}{m + w}\right) \times 100 = \left(\frac{4w}{5w}\right) \times 100 = 80\% \] - Percentage of women: \[ \text{Percentage of women} = \left(\frac{w}{m + w}\right) \times 100 = \left(\frac{w}{5w}\right) \times 100 = 20\% \] ### Final Answer: - Percentage of men = 80% - Percentage of women = 20%

To solve the problem, we will use the concept of weighted averages. Let's denote the number of men as \( m \) and the number of women as \( w \). ### Step-by-Step Solution: 1. **Understand the Given Information**: - Mean age of the combined group (men and women) = 25 years - Mean age of men = 26 years - Mean age of women = 21 years ...
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