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If earth is supposed to be a sphere of radius R , if `g_(30)` is value of acceleration due to gravity at latitude of `30^(@)` and g at the equator, the value of `g-g_(30^(@))` is

A

`(1)/(4)omega^(2)R`

B

`(3)/(4)omega^(2)R`

C

`omega^(2)R`

D

`(1)/(2)omega^(2)R`

Text Solution

Verified by Experts

The correct Answer is:
B
`g-g_(30^(@))=omega^(2)Rcos^(2)30^(@)=(3)/(4)omega^(2)R`
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