A magnet is suspended horizontal in the earth's magnetic field. When it is displaced and then released it oscillates in a horizontal plane with a period T. If a place of wood of the same moment of inertia (about the axis of rotation) as the magnet is attached to the magnet what would the new period of oscillation of the system become?

Options

A. `(T)/(3)`
B. `(T)/(2)`
C. `(T)/(sqrt(2))`
D. `sqrt(2)T`

Answer

D

Explanation

T=`2pisqrt((I)/(MB_(H)))`
`T^(')=2pisqrt((2I)/(MB_(H)))`
=`sqrt(2)`T