10 g of ice at `0^@C` is mixed with 100 g of water at `50^@C`. What is the resultant temperature of mixture

Options

A. `31.2^(@)`C
B. `32.8^(@)` C
C. `36.7^(@)`C
D. `38.2^(@)`C

Answer

D

Explanation

`theta_("mix")=(m_(w)theta_(w)-(m_(i)L_(i))/(c_(w)))/(m_(i)+m_(w))`
`=(100xx50xx-10xx(80)/(1))/(10+100)`
=`38.2^(@)`C