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Calculate standard free energy change fo...

Calculate standard free energy change for the reaction `2Ag+2H^(+)rarrH_(2)+2Ag^(+)` Given : `E_(Ag^(+)//Ag)^(@)=+0.80V`

A

308.08 kJ

B

154.4 kJ

C

77.2 kJ

D

`-154.4` kJ

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(cell)^(@)+E_(H_(2))^(@)-E_(Ag)^(@)`
= 0-0.80 = 0.80
`DeltaG^(@)= -nFE_(cell)^(@)` = `-2xx96500xx(-1.80)`
=+154.4kJ
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