Q. Two students while solving a quadratic equation in x, one copied the constant term incorrectly and got the roots as 3 and 2. The other copied the constant term and coefficient of `x^2` as `-6` and 1 respectively. The correct roots are :

Options

A. 3, -2
B. `-3, 2`
C. `-6, -1 `
D. `6, -1`

Answer

D

Explanation

Let quandratic equation `x^(2)+bx-6=0` ltBrgt `overset("constant term = wrong")overset(downarrow)("wrong roots=3, 2")`
but sum of roots = 3+2
It means, 3+2 = `(-b)/(1)`
b = -5 correct
`rArrx^(2)-5x-6=0` ltBrgt (x+1)(x-6)=0
x=-1, 6 roots